So I have a game where you can many different dog breeds, including wolf nor coyote hybrids. But in my first *if statement, the human are supposed to react differently if your a hybrid vs a non hybrid.
EX:
*if (multiple hybrids listed here, don’t know how)
Human flinches.
*else
The human shouts at you.
I don’t know how to make an *if with multiple breeds, but I would rather not do one long *if of four of those
So I don’t want this:
*if Wolfdog
human flinches
*if coydog
human flinches
*else
human shouts
You could put them in nested parentheses, like this:
*if (((breed = "wolfdog") or (breed = "coydog")) of (breed = "other hybrid"))
Or, if you want to check this a lot, just make another variable for whether or not the dog is a hybrid, and set it true or false when you choose the breed. Then all you’d have to write is
*if dog_is_hybrid
Human flinches
*if not (dog_is_hybrid)
Human shouts
So I tried the first thing, with the parenthesis, but then I got this:
stray1 line 7: Invalid expression at char 95, expected no more tokens, found: CLOSE_PARENTHESIS [)]
There are 5 breeds for the *if, do I need to set a new *set code? I’m still new to this program, first time i’ve done multiple *if
Every time you add a condition, you need to add another set of parentheses around the whole thing. This is because choicescript can only process two things at a time, so you have to put everything in pairs. Honestly, it sounds like this is going to be a significant detail in your game and I’d recommend making a specific variable for it. But it is handy to know how to write if statement with multiple conditions in case you need to. 5 would look something like this:
*if (((((breed = "hybrid1") or (breed = "hybrid2")) or (breed = "hybrid3")) or (breed = "hybrid4")) or (breed = "hybrid5"))
If you want to use an extra variable, you’d need to create it in the startup menu with your other variables, then set it when the player chooses a breed later. So, in your startup menu: *create dog_is_hybrid false and at the choice something like: